(x+3)(x+5)-(x^2-3x)=x

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Solution for (x+3)(x+5)-(x^2-3x)=x equation: 



(x+3)(x+5)-(x^2-3x)=x

We move all terms to the left:

(x+3)(x+5)-(x^2-3x)-(x)=0

We add all the numbers together, and all the variables

-1x+(x+3)(x+5)-(x^2-3x)=0

We get rid of parentheses

-x^2-1x+(x+3)(x+5)+3x=0

We multiply parentheses ..

-x^2+(+x^2+5x+3x+15)-1x+3x=0

We add all the numbers together, and all the variables

-1x^2+(+x^2+5x+3x+15)+2x=0

We get rid of parentheses

-1x^2+x^2+5x+3x+2x+15=0

We add all the numbers together, and all the variables

10x+15=0

We move all terms containing x to the left, all other terms to the right

10x=-15

x=-15/10

x=-1+1/2

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